0=(5x^2)+28x+51

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Solution for 0=(5x^2)+28x+51 equation: 



0=(5x^2)+28x+51

We move all terms to the left:

0-((5x^2)+28x+51)=0

We add all the numbers together, and all the variables

-(5x^2+28x+51)=0

We get rid of parentheses

-5x^2-28x-51=0

a = -5; b = -28; c = -51;
Δ = b2-4ac
Δ = -282-4·(-5)·(-51)
Δ = -236
Delta is less than zero, so there is no solution for the equation

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